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A laboratory experiment involves measuring the refractive index of a liquid using a travelling microscope. The main scale reading is 3.0 mm, and the vernier scale reading is 0.45 mm. The microscope’s least count is 0.01 mm, and each main scale division is equal to 0.5 mm on the object being observed. Determine the refractive index of the liquid.

Option: 1

3.0045


Option: 2

2.0248


Option: 3

4.6520


Option: 4

1.3625


Answers (1)

best_answer

Given values:

Main scale reading (M) = 3.0 mm
Vernier scale reading (V ) = 0.45 mm
Least count (LC) = 0.01 mm
Main scale division (D) = 0.5 mm

The total reading of the microscope can be calculated by adding the main scale reading to the product of the vernier scale reading and the least count:

                    Total reading = M + (V * LC)

Step 1: Calculate the total reading of the microscope:

                    Total reading = 3.0 mm + (0.45 * 0.01 mm) = 3.0 mm + 0.0045 mm = 3.0045mm

The actual reading on the object can be found using the formula:

                    Actual reading = Total reading * D

Step 2: Calculate the actual reading on the object:

                    Actual reading = 3.0045 mm * 0.5 mm = 1.50225 mm

The refractive index of the liquid can be calculated using the formula:

                    Refractive index = Actual reading / D

Step 3: Calculate the refractive index:

                       Refractive index

                                = \frac{1.50225 mm}{0.5 mm} = 3.0045 

The refractive index of the liquid is 3.0045.

                    

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jitender.kumar

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