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A large metal sheet carries a electric current along its surface current per unit lenght is \lambda. Magnetic field induction near the metal surface is

Option: 1

\lambda \mu o


Option: 2

\frac{\lambda \mu o}{2}


Option: 3

\frac{\lambda \mu o}{2\pi}


Option: 4

\frac{ \mu o}{2\pi \lambda}


Answers (1)

best_answer

As we learned

Magnetic field in Infinite sheet carrying current -

B=\frac{\mu _{o}j}{2}

J\rightarrowcurrent density 

- wherein

 

 Use ampere circuital law

\oint \vec{B}\cdot \overrightarrow{dl}=\mu oI

2Bl=\mu o(\lambda l)

B=\frac{\mu o\lambda }{2}

 

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himanshu.meshram

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