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A light ray is incident on a glass sphere of refractive index  \mu =\sqrt{3} at an angle of incidence 60as shown the total deviation after two refraction is 

Option: 1

300


Option: 2

450


Option: 3

750


Option: 4

600


Answers (1)

best_answer

At point A:

1. \sin 60^{0}=\sqrt{3}\sin r

\Rightarrow r= 30^{0}

from symmetry 

r{'}=r= 30^{0}

Apply snell's law at B

1. \sin e=\sqrt{3}\sin r{'}=\frac{\sqrt{3}}{2}

\Rightarrow e=60^{0}

\delta _{1}= 60^{0}-30^{0}=30^{0}

\delta _{2}=e-r^{1}= 60^{0}-30^{0}=30^{0}

\therefore total deviation =600

Posted by

manish painkra

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