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A long cylindrical conductor of radius R and \sigma=\infty carries a current I=I_0 \sin \omega t. As a function of radius r ( for\ r \geqslant R ), then the conduction current density J(r) is -

Option: 1

\sigma \bar{E}


Option: 2

\frac{I_{0}r}{\pi\ R^{2}}


Option: 3

Zero


Option: 4

\frac{I_{0}}{2\pi\ r}


Answers (1)

best_answer

The conduction current density is given by-
\begin{aligned} J(r) & =\frac{I}{\pi R^2}=\frac{I_0 \sin \omega t}{\pi R^2} \text { fo } 0 \leqslant r \geqslant R \\ & =0 \quad \text { for } \quad r \geqslant R \end{aligned} \\ For\ r \geqslant R\ denesity\ become\ Zero.
 

Posted by

himanshu.meshram

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