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  • A man weighs 80 Kg . He stands on a weighing machine in a lift which is moving upwards with a uniform acceleration of <img alt="5 m/s^2" src="https://learn.careers360.com/latex-image/?5%20m/s%

A man weighs 80 Kg . He stands on a weighing machine in a lift which is moving upwards with a uniform acceleration of 5 m/s^2 .what would be the reading on the machine (g = 10 m/s^2)

Option: 1

1200


Option: 2

zero 


Option: 3

400 N 


Option: 4

100 N 


Answers (1)

best_answer

As we have learned

Lift is accelerating Upward with acceleration = a -

v=variable,


a< g


R-mg=ma

R=m(g+a)

- wherein

Apparent weight > Actual weight

 

 

R - mg = ma 

R = m (g+a)

R = 80 (10+5) 

R = 1200 N 

So apparent weight on the machine will be 1200 N 

 

 

 

Posted by

Shailly goel

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