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A mass ‘m’ is supported by a massless string wound around a uniform hollow cylinder of mass m and radius R.  If the string does not slip on the cylinder, with what acceleration will the mass fall on release ?

Option: 1

\frac{2g}{3}


Option: 2

    \frac{g}{2}


Option: 3

\frac{5g}{6}


Option: 4

g


Answers (1)

best_answer

\\ mg-T=ma \\ \\ For \: cylinder \\ \\ TR=mr^{2}\frac{a}{R} \: \: \Rightarrow T=ma \\ \\ mg=2ma \\ \\ a=\frac{g}{2}

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Ritika Harsh

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