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A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index \frac{5}{3} is poured inside the bucket, then microscope have to be raised by 30 \mathrm{~cm} to focus the object again. The height of the liquid in the bucket is :

Option: 1

12 \mathrm{~cm}


Option: 2

50 \mathrm{~cm}


Option: 3

18 \mathrm{~cm}


Option: 4

75 \mathrm{~cm}


Answers (1)

best_answer

\mathrm{d}_{\mathrm{app}}=\frac{\mathrm{d}}{\mu}=\frac{\mathrm{h}}{(5 / 3)}
\mathrm{Shift}=\mathrm{h} -\frac{3 \mathrm{~h}}{5}=30
\mathrm{h}=75 \mathrm{~cm}

Posted by

Gautam harsolia

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