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A monoatomic gas is going under adiabatic process . adiabatic elasticity at pressure P = 10 ^3 N/ m^2  is K times 10 ^3 N/ m^2  then value of K is 

Option: 1

1.67


Option: 2

1.50


Option: 3

1.4 


Option: 4

1.3


Answers (1)

best_answer

As we have learned

Elasticity in the adiabatic process -

E= \frac{stress}{strain}

= -\frac{dP}{dV/V}
 

- wherein

E= -V\left ( -\gamma \frac{P}{V} \right )

E= \gamma P

 

 For adiabatic process PV^\gamma = constant \: \: di\! f\! \! f\! erentiating \: \: both \: \: side

dPV^\gamma + P\gamma V^{\gamma -1}dV = 0

\gamma P = \frac{dP}{-dV/V} = \frac{stress }{strain } = elasticity \\\\ adiabatic \: \: elasticity = \gamma P \\\\ = 5/3 \times 10 ^3 \\\\ = 1.67 \times 10 ^ 3

 

Posted by

shivangi.shekhar

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