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  • A parachutist after bailing out falls 50 m without friction. When the parachute opens, it decelerates at 2 m/s2. He reaches the ground at a speed of 3 m/s. At what height (in meters), di

A parachutist after bailing out falls 50 m without friction. When the parachute opens, it decelerates at 2 m/s2. He reaches the ground at a speed of 3 m/s. At what height (in meters), did he bail out?

Option: 1

293


Option: 2

111


Option: 3

91


Option: 4

182


Answers (1)

best_answer

initially, the parachutist falls under gravity

u^{2}= 2ah= 2\times 9.8\times 50= 980 m^{-2}s^{-2}

He reaches the ground with speed

= 3m/s,a= -2ms^{-2}

\therefore \left ( 3 \right )^{2}= u^{2}-2\times 2\times h_{1}

or\: \: 9= 980-4h_{1}

or\: \: h_{1}=\frac{971}{4}

or\: \: h_{1}=242.75m

\therefore Total\: height\: = 50 + 242.75

= 292.75

= 293m

Posted by

HARSH KANKARIA

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