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A parallel beam of light is allowed to fall on a transparent spherical globe of diameter 30 \mathrm{~cm} and refractive index 1.5. The distance from the centre of the globe at which the beam of light can converge is ___________\mathrm{mm}.

Option: 1

225


Option: 2

114


Option: 3

324


Option: 4

12


Answers (1)

best_answer

\mathrm{1^{st}refraction\\ }

\mathrm{\frac{1.5}{v}-\frac{1}{\infty}=\frac{1.5-1}{+15} }

\mathrm{V_{1}=45\: cm}

For 2^{nd} refraction

\mathrm{\begin{aligned} &\frac{1}{V_{2}}-\frac{1.5}{+15}=\frac{1-1.5}{-15} \\ &\frac{1}{V_{2}}=\frac{1}{10}+\frac{1}{30}=\frac{4}{30} \\ &V_{2}=+7.5 \mathrm{~cm} \end{aligned}}

Distance from centre

=15+7.5

=22.5\mathrm{cm}=225\mathrm{mm}

Hence the correct answer is 225

Posted by

Irshad Anwar

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