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A password consists of 4 letters, where each letter can be either a vowel (a, e, i, o, u) or a consonant. However, consecutive letters cannot be the same. How many different passwords are possible?

 

Option: 1

25,000


Option: 2

36,450


Option: 3

15,600


Option: 4

56,000


Answers (1)

best_answer

For the first position, there are 5 options (vowels: a, e, i, o, u) and 21 options (consonants) available.

For the second position, if the first letter is a vowel, there are 4 options left for a vowel (excluding the one chosen for the first position) and 21 options for a consonant. If the first letter is a consonant, there are 5 options left for a vowel and 20 options for a consonant.

For the third position, if the second letter is a vowel, there are 4 options left for a vowel and 20 options for a consonant. If the second letter is a consonant, there are 5 options left for a vowel and 19 options for a consonant.

For the fourth position (last letter), there must be a vowel because consecutive letters cannot be the same. Therefore, there are 5 options for a vowel.

To find the total number of possible passwords, we multiply the number of options for each position:

(5 vowels or 21 consonants)\times (4 vowels or 21 consonants) \times (4 vowels or 20 consonants)\times (5 vowels) = (5 + 21)\times (4 + 21)\times (4 + 20) \times 5 = 26 \times 25 \times 24\times 5 = 15,600.

Therefore, there are 15,600 different passwords possible.

 

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