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  • A pendulum of length consists of a wooden bob of mass <img alt="\mathrm{50g}" src="https://entrance

A pendulum of length \mathrm{2m} consists of a wooden bob of mass \mathrm{50g}. A bullet of mass \mathrm{75 g} is fired towards the stationary Bob with a speed \mathrm{v}. The bullet emerges out of the Bob with a speed \mathrm{\frac{v}{3}} and the Bob just completes the vertical circle. The value of \mathrm{v} is _______\mathrm{ms^{-1}}.

( if \mathrm{g=10m/s^{2}} ).

Option: 1

10


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Linear momentum conservation

\mathrm{75 \times V =50 \times V^{\prime}+75 \times \frac{V}{3}} \\

\mathrm{V^{\prime} \times 50 =2 \times \frac{75}{3} \times V} \\

\mathrm{V^{\prime} =\frac{2 \times 75}{50 \times 3} \times V} \\

      \mathrm{=\frac{2 \times 3}{2 \times 3} V=V}

The bob just completes the vertical circular motion

\mathrm{\therefore V =\sqrt{5 \mathrm{gl}}} \\

\mathrm{V =\sqrt{5 \times 10 \times 2}} \\

\mathrm{V =10 \mathrm{~m} / \mathrm{s}}

Hence answer is \mathrm{10} \\.

Posted by

seema garhwal

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