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  • A person of mass M is standing on lift. If lift moves vertically upwards according to given v-t graph then find out the apparent weight of man at t = 1 sec. (g = 10m/s2) <

A person of mass M is standing on lift. If lift moves vertically upwards according to given v-t graph then find out the apparent weight of man at t = 1 sec. (g = 10m/s2)

 

Option: 1

20 M


Option: 2

10 M


Option: 3

5 M


Option: 4

15 M 


Answers (1)

best_answer

Solution :

Apparent weight of body in a lift  When Lift is moving up with a = g

R-mg=mg

R=2mg 

Apparent weight = 2 (Actual weight)

 So Accelaration of  person at t = 1 sec is 

a= \frac{20-0}{2-0}=10m/s^{2}

 R=m(g+a)=\left ( 10+10 \right ) M

R = 20 M 

 

Posted by

Deependra Verma

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