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A point has position vector \vec{\gamma }=2\hat{i}-3\hat{j}+5\hat{k} then sum of its co-ordinates equals

Option: 1

4


Option: 2

5


Option: 3

6


Option: 4

7


Answers (1)

best_answer

As we learned,

Position vector of a point -

\overrightarrow{OP}= \hat{xi}+y\hat{j}+z\hat{k}

- wherein

Fig 5

 

 \vec{\gamma }=2\hat{i}-\hat{j}+5\hat{k}, so x-co-ordinate is 2

y-co-ordinate is -3 & z-co-ordinate is 5.

\therefore Sum of co-ordinates = 2+(-3)+5=4

So, option (A)

 

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Nehul

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