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  • A point object, 'O' is placed in front of two thin symmetrical coaxial convex lenses  and <

A point object, 'O' is placed in front of two thin symmetrical coaxial convex lenses L_{1} and L_{2} with focal length 24 cm and 9 cm respectively. The distance between two lenses is 10 cm and the object is placed 6 cm away from lens L_1  as shown in the figure. The distance between the object and the image formed by the system of two lenses is __________ cm.

Option: 1

34


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Due to lens \mathrm{L}_1

 

\begin{aligned} & u=-6 cm \\ & f=+24 cm \\ & \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\ & \frac{1}{v}=\frac{1}{24}-\frac{1}{6}=\frac{1-4}{24} \Rightarrow v=-8 \ c m \end{aligned}

Due to lens \mathrm{L}_2

\begin{aligned} & \mathrm{U}=-18 \mathrm{~cm} \\ & \mathrm{~F}=+9 \mathrm{~cm} \\ & \frac{1}{\mathrm{v}}-\frac{1}{\mathrm{u}}=\frac{1}{\mathrm{f}} \mathrm{x} \\ & \frac{1}{\mathrm{v}}-\frac{1}{9}=\frac{1}{18} \\ & \mathrm{~V}=\frac{1}{\mathrm{v}}=\frac{2-1}{18} \\ & \mathrm{~V}=18 \mathrm{~cm} \end{aligned}

So The distance between the object and the image formed by the system of two lenses is (6+10+18=34 cm)

Posted by

Devendra Khairwa

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