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A point source of light S, placed at a distance 60cm infront of the centre of a plane mirror width 50 cm, hangs vertically on a wall. A man walks infront of the mirror along a line parallel to the mirror at a distance 1.2 m from it (see in the figure). The distance between the extreme points where he can see the image of the light source in the mirror is _________cm.
Option: 1 150
Option: 2 300
Option: 3 75
Option: 4 120

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\begin{aligned} &\tan \theta=\frac{25}{60}=\frac{x}{180}\\ &\mathrm{x}=75 \mathrm{~cm}\\ &\text { so distance between extreme point }=2 \mathrm{x}=2 \times &75=150 \mathrm{~cm} \end{aligned}

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Deependra Verma

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