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  • A projectile of mass M is fired so that the horizontal range is 4 Km. At the highest point the projectile explodes in two parts of masses M/4 and 3M/4 respectively and the heavier part starts falli

A projectile of mass M is fired so that the horizontal range is 4 Km. At the highest point the projectile explodes in two parts of masses M/4 and 3M/4 respectively and the heavier part starts falling down vertically with zero initial speed. The horizontal range (distance from point of firing )of the lighter part is :

Option: 1

16 Km


Option: 2

1 Km


Option: 3

10 Km


Option: 4

2 Km


Answers (1)

best_answer

 

 

 

 

 

 

X_{C O M}=\frac{m_{1} x_{1}+m_{2} x_{2}}{m_{1}+m_{2}}

\begin{array}{l} R=\frac{\frac{M}{4} x+\frac{3 M}{4} \times \frac{R}{2}}{M} \\ \\ \Rightarrow x=10 \mathrm{Km} \end{array}

 

 

Posted by

Ritika Harsh

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