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  • A radioactive nucleus undergoes a series of decay according to the scheme <img alt="\mathrm{A} \stackrel{\alpha}{\longrightarrow} \mathrm{A}_1 \stackrel{\beta}{\longrightarrow} \mathrm{A}

A radioactive nucleus undergoes a series of decay according to the scheme

\mathrm{A} \stackrel{\alpha}{\longrightarrow} \mathrm{A}_1 \stackrel{\beta}{\longrightarrow} \mathrm{A}_2 \stackrel{\alpha}{\longrightarrow} \mathrm{A}_3 \stackrel{\gamma}{\longrightarrow} \mathrm{A}_4

If the mass number and atomic number of A are 180 and 72 respectively, these numbers of \mathrm{A}_4 are:

Option: 1

172, 69 


Option: 2

177, 69


Option: 3

171, 69


Option: 4

172, 68


Answers (1)

best_answer

Decrease in mass number of due to two \alpha=2 \times 4=8

Decrease in charge number due to two \alpha=4

Increase in charge number due to one  \beta=1

Net decrease in charge number =4-1=3

\gamma affects neither. 

\therefore \quad \text { For } A_4, A=180-8=172

            Z=72-3=69

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