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A ray of light is incident at an angle of 60^{\circ} on one face of a prism of angle 30^{\circ}. The emergent ray of light makes an angle of 30^{\circ} with incident ray. The angle made by emergent ray with second face of prism will be:

Option: 1

0^{\circ}


Option: 2

90^{\circ}


Option: 3

45^{\circ}


Option: 4

30^{\circ}


Answers (1)

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Here, \mathrm{\mathrm{i}_1=60^{\circ}, \mathrm{A}=30^{\circ}, \delta=30^{\circ}, \mathrm{i}_2=?}
As \mathrm{\mathrm{i}_1+\mathrm{i}_2=A+\delta }
\mathrm{ \therefore \quad \mathrm{i}_2=\mathrm{A}+\delta-\mathrm{i}_1=30^{\circ}+30^{\circ}-60^{\circ}=0^{\circ} }
Angle of emergent ray with second face of prism
\mathrm{=90^{\circ}-0^{\circ}=90^{\circ}}

Posted by

HARSH KANKARIA

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