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  • A sample of a radioactive nucleus A disintegrates to another radioactive nucleus B, which in turn disintegrates to some other stable nucleus . Plot of a graph sho

A sample of a radioactive nucleus A disintegrates to another radioactive nucleus B, which in turn disintegrates to some other stable nucleus \mathrm{C}. Plot of a graph showing the variation of number of atoms of nucleus B vesus time is :
(Assume that at t=0, there are no B atoms in the sample)
Option: 1
Option: 2
Option: 3
Option: 4

Answers (1)

best_answer

A\overset{\lambda _{A}}{\rightarrow}B\overset{\lambda _{B}}{\rightarrow}C
\left ( N_{A} \right )_{t}= \left ( N_{A} \right )_{0}e^{-\lambda _{A}t}\rightarrow \left ( 1 \right )
After time t, the no.of nuclei of B,
\left ( N_{B} \right )_{t}=\left [ \left ( \left ( N_{A} \right )_{0} -\left ( N_{A} \right )_{t}\right ) \right ]+\left ( N_{B} \right )_{0}e^{-\lambda_{B}t }
\left ( N_{B} \right )_{t}=\left ( N_{A} \right )_{0} \left ( 1-e^{-\lambda _{A}t} \right )+\left ( N_{B} \right )_{0}e^{-\lambda _{B}t}
but\: \left ( N_{B} \right )_{0}=0
\left ( N_{B} \right )_{t}=\left ( N_{A} \right )_{0}\left ( 1-e^{-\lambda _{A}t} \right )
The correct option is (3)

Posted by

vishal kumar

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