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A shopkeeper has 10 copies each of nine different books, then number of ways in which atleast one book can be selected is

Option: 1

9 ^{11} - 1


Option: 2

10 ^{10} - 1


Option: 3

11 ^{9} - 1


Option: 4

10 ^9


Answers (1)

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As we have learnt,

The number of ways of selecting at least one item from a collection of m objects of one kind, n objects of another kind and p of yet another kind is

(m + 1) (n + 1) (p + 1) - 1

 

Now,

\underbrace{B_1} 10 \: \: \underbrace{B_2 }10 \: \: \underbrace{B_3}10 \: \: \,\,\,\,\,\,\,\,......\,\,\,\,\,\,\,\,\,\,\underbrace{B_9} 10 

So, number of ways of selection of atleast one book is 

\underbrace{(10+1)(10+1)...(10+1) -1}   

                          9 times 

11^9-1

                             

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shivangi.shekhar

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