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A short-circuited coil is placed in a time varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to be quadrupled and the wire radius halved, the electrical power dissipated would be :

Option: 1

halved


Option: 2

the same


Option: 3

doubled


Option: 4

quadrupled


Answers (1)

best_answer

Power P=\mathrm{\frac{e^2}{R} }
Here, \mathrm{e= induced \, \, emf =-\left(\frac{d \phi}{d t}\right) where\, \, \phi=N B A }

\mathrm{e=-N A\left(\frac{d B}{d t}\right) }

Also,\mathrm{ \quad R \propto \frac{l}{r^2} }
where R= resistance, r= radius, I= length
\mathrm{ \begin{array}{ll} \therefore & P \propto \frac{N^2 r^2}{l} \\ \therefore & \frac{P_1}{P_2}=1 \end{array} }

Posted by

Rishabh

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