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  • A solution is prepared by mixing 8.5 g of CH2Cl2 and 11.95 g of CHCl3.  If vapour pressure of CH2Cl2 and CHCl3 at 298 K are 415 and 200 mmHg respectively, the mole fraction of CHCl<

A solution is prepared by mixing 8.5 g of CH2Cl2 and 11.95 g of CHCl3.  If vapour pressure of CH2Cl2 and CHCl3 at 298 K are 415 and 200 mmHg respectively, the mole fraction of CHCl3 in vapour form is : (Molar mass of Cl=35.5 g mol−1)  
Option: 1  0.162
Option: 2 0.675
Option: 3 0.325
Option: 4  0.486  
 

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