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  • A solution of x moles of sucrose in 100gms of water freezes at -0.2°C. As ice separates the freezing point goes down to -0.25°C. How many grams of ice would have separated? (Respo

A solution of x moles of sucrose in 100gms of water freezes at -0.2°C. As ice separates the freezing point goes down to -0.25°C. How many grams of ice would have separated?

(Response should be only in integer like 78 or 40).

Option: 1

18


Option: 2

20


Option: 3

25


Option: 4

35


Answers (1)

best_answer

Depression in freezing point -

Mathematical Expression of Depression in Freezing point -

\Delta T_{f}= K_{f}\: m

(molality)_=\frac{x\times 1000}{100}= \frac{0.2}{K_{f}}                        .....................(1)

(molality)_{f}=\frac{x\times 1000}{w}= \frac{0.25}{K_{f}}                     .......................(2)

(1) / (2)

So, \frac{0.2}{0.25} = \frac{w}{100}

\Rightarrow so, w = 80gm

Hence ice separated = 20 gm

Posted by

Rishabh

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