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A steel rod bas a radius of 20 mm and a length of 2.0 m. A force of 62.8 kN stretches it along its length. Young's
modulus of steel is 2.0 × 1011 N/m2 . The longitudinal strain produced in the wire is _______ × 10-5

Option: 1

25


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & Y=\frac{\text { stress }}{\text { strain }} \\ & \Rightarrow \text { strain }=\frac{\text { stress }}{Y}=\frac{F}{A Y}=\frac{62.8 \times 1000}{\pi r^2 \times 2 \times 10^{11}}=\frac{62.8 \times 1000}{3.14 \times 400 \times 10^{-6} \times 2 \times 10^{11}}=\frac{200}{8} \times 10^{-5}=25 \times 10^{-5} \end{aligned}

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Anam Khan

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