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A tank contains water on top of mercury as shown in figure. A cubical block of side 10cm is in equilibrium inside the tank. The depth of the block inside mercury is (RD of the material of block = 8.85, RD of mercury = 13.6)

Option: 1

6cm


Option: 2

5cm


Option: 3

7cm


Option: 4

8cm


Answers (1)

best_answer

Weight = upthrust from mercury + upthrust from water \therefore \quad 10 \times 8.56=(x \times 13.6)+(10-x) \times 1.0

Here, x = depth inside mercury

85.6=13.6 x+10-x

x=6cm

Posted by

Rakesh

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