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A thermodynamic system is taken from an original state \mathrm{D} to an intermediate state \mathrm{E} by the linear process shown in the figure. Its volume is then reduced to the original volume from \mathrm{E}$ to $\mathrm{F} by an isobaric process. The total work done by the gas from \mathrm{D}$ to $\mathrm{E}$ to $\mathrm{F} will be

Option: 1

-450 \mathrm{~J}


Option: 2

450 \mathrm{~J}


Option: 3

900 \mathrm{~J}


Option: 4

1350 \mathrm{~J}


Answers (1)

best_answer

In process DEF

\mathrm{W=( Area \: of \operatorname{loop}) }

      \mathrm{=\frac{1}{2} \times 3 \times 300 }

\mathrm{W =450 \mathrm{~J}}

Hence 2 is correct option
 

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