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A thin mica sheet of thickness 4 \times 10^{-6} \mathrm{~m} and refractive index (\mu=1.5) is introduced in the path of the light from upper slit. The wavelength of the wave used in \mathrm{ 5000\, \AA}. The central bright maximum will shift:

Option: 1

4 fringes upward


Option: 2

2 fringes downward


Option: 3

10 fringes upward


Option: 4

none of these


Answers (1)

best_answer

On introducing mica sheet, fringe shift\mathrm{ =\frac{\beta}{\lambda}(\mu-1) \mathrm{t}}

Where, t is thickness of sheet.

So, shift \mathrm{ =\frac{\beta}{\left(5000 \times 10^{-10}\right)} \times(1.5-1) \times\left(4 \times 10^{-6}\right)=4 \beta}

So, central bright maximum will shift 4 fringes upward.

Posted by

Anam Khan

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