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A  uniform straight rod of length L, mass M has Moment of inertia about an axis through its centre and perpendicular to it
as I. If we take new rod of length 2L, mass \left ( 0.5\; M \right ), Then Moment of inertia of new rod about an axis through its centre and
perpendicular to it will be

Option: 1

I


Option: 2

2I


Option: 3

3I


Option: 4

4I


Answers (1)

best_answer

 

 

Moment of inertia of a Rod is given as  I=\frac{ML^{2}}{12}

Now take {M}'=0.5M and {L}'=2L

SO, {I}'=\frac{{M}'{L}'^{2}}{12}=\frac{\frac{1}{2}M\ast 4L^{2}}{12}=2I

 

Posted by

Gunjita

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