Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A Vernier Caliper has 0.5 mm marks on the main scale. It has 25 equal divisions on the Vernier scale which match with 24 ma

A Vernier Caliper has 0.5 mm marks on the main scale. It has 25 equal divisions on the Vernier scale which match with 24 main scale divisions. For this Vernier calipers, the least count is

Option: 1

0.02 mm


Option: 2

0.05 mm


Option: 3

0.04 mm


Option: 4

0.2 mm


Answers (1)

best_answer

The least count may be calculated as the ratio between the smallest division on the main scale by the number of divisions on the vernier scale.

So, 25 divisions of vernier scale = 24 divisions of main scale.

Therefore, 1 VSD = \frac{24}{25} \, =0.96 \, mm

Also, Least count = 1MSD - 1VSD

= 1mm - 0.96 mm

= 0.04 mm

So. the correct option is C.

Posted by

Info Expert 30

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: NIT Rourkela cut-offs for CSE, chemical engineering drop; last years' closing ranks
anam-khan

JEE Main 2025 Live: NTA exam city slip at jeemain.nta.nic.in soon; session 1 schedule
anam-khan

JEE Main 2025 schedule out for session 1; paper 1 from January 22

Latest Question