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Screenshot_2019-03-02-15-01-13-335_com.android.chrome.png A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is v , the total area around the fountain that gets wet is

Answers (1)

Horizontal Range -

Horizontal distance travelled by projectile from the point of projectile to the point on ground where its hits.

R=\frac{u^{2}\sin 2\Theta }{g}

- wherein

Special case of horizontal range

For max horizontal range.

\Theta = 45^{0}

R_{max}=\frac{u^{2}\sin 2 (45) }{g}=\frac{u^{2}\times 1}{g}=\frac{u^{2}}{g}

 

 R_{max}=\frac{v^2_0sin 90^{o} }{g}=\frac{v^2_0}{g}

Area=\Pi (R_{max})^2 \: =\frac{\Pi v^4_0}{g^2}

Posted by

Safeer PP

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