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2. An ac circuit the current is given by i=4sin(100t+30) ampere. The current becomes maximum first time (after t=0) at t equal to

a)(1/200)sec   b) (t1/300)sec    c) (1/50)sec    d) none of these

3. The instantaneous value of current in an ac circuit is i=2sin(100t+/3)A. The  current at the beginning (t=0) will be

 

Answers (2)

@ Mannika

Q2

i = 4sin(100\pi t + 30\degree)

i will be maximum when sin(100\pi t + 30\degree) will be maximum that is it will be equal to 1.

\Rightarrow 100\pi t+\frac{\pi }{6} = \frac{\pi}{2}

\Rightarrow t = \frac{1}{300}\: sec

 

Posted by

Abhishek Sahu

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@Mannika

i = 2sin(100\pi t+\frac{\pi}{3})

At t = 0

i = 2sin(100\pi \times 0+\frac{\pi}{3})

\Rightarrow i = 2sin(\frac{\pi}{3})

i = \sqrt{3}A

Posted by

Abhishek Sahu

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