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  • An aqueous KCl solution of density has a molality of <img alt="\mathrm{3. 30\, mol\, kg^{-1}}" src="http

An aqueous KCl solution of density \mathrm{1.20\, g\, mL^{-1}} has a molality of \mathrm{3. 30\, mol\, kg^{-1}}. The molarity of the solution in \mathrm{mol\, L^{-1}} is _______.(Nearest integer) [Molar mass of KCl = 74.5]
 

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best_answer

Given,

\mathrm{molality= 3. 3\, mol\, kg^{-1}}

\mathrm{density= 1. 20\,g\, mL^{-1}}

Let, 1kg of solvent be taken .

\mathrm{\therefore moles\, of\, KCl= 3. 3}

\mathrm{\therefore mass\, of\, KCl= 3. 3\times 74.5 = 245.85\ g}

  \mathrm{Thus, total \, mass \, of \, solution = 1245. 85\, g}

And, 

\begin{aligned} \mathrm{\therefore volume\, of\, solution} & = \frac{1245. 85}{1.2}\, \text{mL} \\ &=1038.2 \, \text{mL} \\ &=1.0382 \, \text{L} \end{aligned}

\mathrm{\therefore M= \frac{3. 3}{1. 0382}= 3. 178\, mol\, L^{-1}}

Hence, the answer is 3.

Posted by

sudhir.kumar

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