Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • An average force of 125 N is applied on a machine gun firing bullets each of mass 10 g at the speed of 250 m/s to keep it in position. The number of bullets fired per second by the machine g

An average force of 125 N is applied on a machine gun firing bullets each of mass 10 g at the speed of 250 m/s
to keep it in position. The number of bullets fired per second by the machine gun is :

Option: 1

25


Option: 2

5


Option: 3

100


Option: 4

50


Answers (1)

best_answer

\begin{aligned} & \mathrm{F}=125 \mathrm{~N} \\ & \mathrm{F}=\frac{\mathrm{dp}}{\mathrm{dt}} \quad \mathrm{n} \rightarrow \text { No. of bullets } \\ \end{aligned}

\begin{aligned} & \mathrm{F}=\frac{\mathrm{d}(\mathrm{nmv})}{\mathrm{dt}}=\mathrm{mv} \frac{\mathrm{dn}}{\mathrm{dt}} \\ & 125=\frac{10 \mathrm{n}}{1000} \times 250 \times \frac{\mathrm{dn}}{\mathrm{dt}} \end{aligned}

\begin{aligned} & \frac{125 \times 1000}{2500}=\frac{\mathrm{dn}}{\mathrm{dt}} \\ & \frac{\mathrm{dn}}{\mathrm{dt}}=50 \end{aligned}

 

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: Most important chapters for physics, chemistry, mathematics to score good marks
anam-khan

JEE Main 2025 session 2 dates clash with ISC, PSEB 12th exams; no impact on major science subjects
anam-khan

Delhi police EOW books FIITJEE for fraud; 192 complaints filed

Latest Question