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An electron and a photon have same wavelength. If p is the momentum of electron and E is the energy of photon. The magnitude of  \frac{p}{E}    in S.I unit is

Option: 1

3.0 \times 10^8


Option: 2

3.33 \times 10^{-9}


Option: 3

9.1 \times 10^{-31}


Option: 4

6.64 \times 10^{-34}


Answers (1)

best_answer
As we know that, for electron,   \lambda_{e} =\frac{h}{p}

or,      p = \frac{h}{\lambda_{e}}

and for photon E = hc/λ

Thus, p/E = 1/c = 1/(3\times108 m/s)

= 3.33  \times 10-9 s/m

Therefore, from the above observation, we conclude that option (2) is correct. 

Posted by

vishal kumar

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