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An electron of mass \mathrm{m} and charge \mathrm{e} initally \mathrm{e} initally at rest gets accelerated by a constant electric field \mathrm{E}. The rate of charge of de - Broglie wave length of this electron at time \mathrm{t}, ignoring relativistic effects is - 

Option: 1

\mathrm{\frac{-h}{e E t^2}}


Option: 2

\mathrm{\frac{-e h t}{E}}


Option: 3

\mathrm{-\frac{m b}{e E t^2}}


Option: 4

\mathrm{-\frac{h}{eE}}


Answers (1)

best_answer

Acceleration, \mathrm{a=\frac{Ee}{m}}
\mathrm{\because a=\frac{f}{m}}
\mathrm{F=eE}
Velocity of electron, \mathrm{v=at}
\mathrm{v=\frac{E e t}{a m}}
weve length, \mathrm{\lambda=\frac{h}{m\ v}=\frac{h m}{m\ Ee t} \Rightarrow \frac{h}{E\ e t}}
Now, Rate of charge of de - Broglie wavelength
\mathrm{\frac{d \lambda}{d t}=-\frac{h}{e E t^2}}

Posted by

Gaurav

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