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  • An inductor (L = 10 0mH), a resistor  and a battery (E = 100 V)

An inductor (L = 10 0mH), a resistor \mathrm{(R=100\: mH)} and a battery (E = 100 V) are initially connected in series as shown in the figure. After a long time, the battery is disconnected after short-circuiting the points A and B. The current in the circuit 1 ms after the short – circuit is:

Option: 1

eA


Option: 2

0.1A


Option: 3

1 A


Option: 4

1/e A


Answers (1)

best_answer

During decay of current

\mathrm{i}=\mathrm{i}_0 \mathrm{e}^{-\frac{\mathrm{Rt}}{\mathrm{L}}}=\frac{\mathrm{E}}{\mathrm{R}} \mathrm{e}^{-\frac{\mathrm{Rt}}{\mathrm{L}}}=\frac{100}{100} \mathrm{e}^{-\frac{100 \times 10^{-3}}{100 \times 10^{-3}}}=\frac{1}{\mathrm{e}} \mathrm{A}

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manish

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