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  • An object 'o' is placed at a distance of in front of a concave mirror of radi

An object 'o' is placed at a distance of 100 \mathrm{~cm} in front of a concave mirror of radius of curvature 200 \mathrm{~cm} as shown in the figure. The object starts moving towards the mirror at a speed 2 \mathrm{~cm} / \mathrm{s}. The position of the image from the mirror after 10 \mathrm{~s} will be at ________\mathrm{cm} .

Option: 1

400


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

After \mathrm{10\: s},the distance of object from mirror will be

\mathrm{u=100-2\times10 =80cm}

\mathrm{ \frac{1}{v}+\frac{1}{u}=\frac{1}{f} }

\mathrm{\frac{1}{v}+\frac{1}{(-80)}=\frac{1}{-100} }

\mathrm{\frac{1}{v}=\frac{1}{20}-\frac{1}{100}=\frac{20}{8000} }

\mathrm{v=400 \mathrm{~cm}}

The position of the image from mirror after 10 s  at \mathrm{400 \mathrm{~cm}}

Posted by

Suraj Bhandari

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