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  • An object of mass 5 kg is thrown vertically upwards from the ground. The air resistance produces a constant retarding force of 10 N throughout the motion. The ratio of time of ascent to the time of

An object of mass 5 kg is thrown vertically upwards from the ground. The air resistance produces a constant retarding force of 10 N throughout the motion. The ratio of time of ascent to the time of descent will be equal to : [Use g = 10ms-2].

Option: 1

1:1


Option: 2

\sqrt{2}:\sqrt{3}


Option: 3

\sqrt{3}:\sqrt{2}


Option: 4

2:3


Answers (1)

best_answer


 Total force cownwards =\mathrm{m g+F=60}
\mathrm{a_{1}}=retardation during ascent=\mathrm{12 \mathrm{~m} / \mathrm{s}^{2}}
 

During descent:

During descent
Total force downward =\mathrm{m g-F} = 40
\mathrm{a_{2}}= refartation during descent =\mathrm{8 \mathrm{~m} / \mathrm{s}}
Time of ascent or descent is
\mathrm{ \begin{aligned} &T=\sqrt{\frac{2 h}{a}} \\ &\therefore \frac{T_{a}}{T_{d}}=\sqrt{\frac{a_{2}}{a_{1}}}=\sqrt{\frac{2}{3}} \end{aligned} }
The correct opfion is (2)

 

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chirag

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