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  • An observer moves towards a stationary source of sound with a velocity equal to one-fifth of the velocity of sound. The percentage change in the frequency will be :<stro

An observer moves towards a stationary source of sound with a velocity equal to one-fifth of the velocity of sound. The percentage change in the frequency will be :

Option: 1

\mathrm{20%}


Option: 2

\mathrm{10%}


Option: 3

\mathrm{5%}


Option: 4

\mathrm{0%}


Answers (1)

best_answer

Doppler's Effect

\mathrm{f^{\prime}=f\left[\frac{V+V_{0}}{V}\right]} \\

\mathrm{f^{\prime}=f\left(\frac{V+\frac{V}{5}}{V}\right)=f \times \frac{\frac{6V}{5}}{V}} \\

\mathrm{f^{\prime}=\frac{6 f}{5}}

Percentage change in frequency

\mathrm{=\frac{f^{\prime}-f}{f} \times 100} \\

\mathrm{=\frac{\frac{6 f}{5}-f}{f} \times 100} \\

\mathrm{=20 \%}

Hence the correct answer is option 1.

Posted by

HARSH KANKARIA

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