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An unblased coin is lossed five times. The outcome of each toss is either a head or a tail. The probability of getting at least one head is
 

Option: 1

\frac{1}{32}
 


Option: 2

\frac{13}{32}
 


Option: 3

\frac{16}{32}
 


Option: 4

\frac{31}{32}


Answers (1)

best_answer

For an unbaised coin, probability of getting head or tail are
\mathrm{ P(H)=\frac{1}{2} \text {, and } P(T)=\frac{1}{2} }
Coin is tossed five times. Hence the probability of getting at least one head
\mathrm{ P=1- } (Probability of not getting any head)

\mathrm{ =1-\left(\frac{1}{2}\right)^5=1-\frac{1}{32} }

\mathrm{ \Rightarrow P=\frac{31}{32} }

 

Posted by

jitender.kumar

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