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  • Analysis of the magnetic moment of the complex  showed the complex to be d

Analysis of the magnetic moment of the complex \mathrm{Ni(CO)_4} showed the complex to be diamagnetic. What is the hybridisation of nickel atom/ion in the complex?

Option: 1

\mathrm{sp^2}


Option: 2

\mathrm{sp^3}


Option: 3

\mathrm{dsp^2}


Option: 4

\mathrm{sp^3d^2}


Answers (1)

best_answer

As we have learnt, 

VBT helps us to predict the hybridisation of the compound if the magnetic moment is known.

It is given that \mathrm{Ni(CO)_4} is diamagnetic. 

In the given complex, \mathrm{Ni} exists as \mathrm{Ni(0)} and has an electronic configuration of \mathrm{d^{10}} in the bonded state.

Thus, the complex has to be \mathrm{sp^3} hybridized as it is a four co-ordinated complex with no inner d orbitals available for the bond formation.

Hence, the correct answer is Option (2)

Posted by

Ritika Kankaria

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