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\overrightarrow{a} and \overrightarrow{b} are two vectors such that \left | \overrightarrow{a} \right |=3, \left | \overrightarrow{b} \right |=4 then maximum possible value of \overrightarrow{a}\cdot \overrightarrow{b} is

Option: 1

10


Option: 2

12


Option: 3

15


Option: 4

7


Answers (1)

best_answer

As we learn

Maximum value of Vector a dot Vector b -

|\vec{a}| |\vec{b}|

-

 

 Maximum value of \vec{a}\cdot \vec{b} is possible when \Theta =0^{0} between \vec{a} and \vec{b}, so(\vec{a}\cdot \vec{b}) maximum  =|\vec{a}| |\vec{b}| =12

 

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Gaurav

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