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Question

X ml of H2 gas effuses through a hole in a container in 5 sec. The time taken for the effusion of the same volume of the  gas specified below under identical conditions is :

A.

10 sec He

B.

20 sec O2

C.

25 sec CO2

D.

55 sec CO2

Answers (1)

best_answer

As we Know

Graham’s law of diffusion -

\dpi{100} r_{1}/r_{2}=\sqrt{M_{1}/M_{2}}  where r is the rate of diffusion of gas, M is molar mass.

Putting given values we get,

\frac{r_{1}}{r_{2}}= \frac{t_{2}}{5}= \sqrt{\frac{M_{2}}{2}}, t_{2} = 20 \: \: sec \: and \: M_{2} = 32

Posted by

Pankaj Sanodiya

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