Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Answer please! A rocket has to be launched from earth in such a way that it never returns. If E is the minimum energy that the launcher shouldhave if the same rocket is to be lunched from the surface of the moon? Assume that the density of the earth

A rocket has to be launched from earth in such a way that it never returns. If E is the minimum energy that the launcher should  have if the same rocket is to be lunched from the surface of the moon? Assume that the density of the earth and the moon are equal and that the earth's volume is 64 times the volume of the moon.

  • Option 1)

    \frac{E}{64}

  • Option 2)

    \frac{E}{32}

  • Option 3)

    \frac{E}{4}

  • Option 4)

    \frac{E}{16}

Answers (1)

best_answer

Given: 

\rho _{moon}=\rho _{earth}

Volume of Earth=64(volume of moon)

\frac{mass\;of\;earth}{mass\;of\;moon}=\frac{\frac{4}{3}\pi R_{e}^{3} \times \rho _{earth}}{\frac{4}{3}\pi R_{m}^{3} \times \rho _{moon}}=\frac{R_{e}^{3}}{R_{m}^{3}}=64

R_{e}=4R_{m} \;\;and \;\; M_{e}=64M_{m}

\frac{E_{earth}}{E_{moon}}=\frac{\frac{GM_{e}m}{R_{e}}}{\frac{GM_{m}m}{R_{m}}}=\frac{M_{e}}{M_{m}}\times \frac{R_{m}}{R_{e}}=64 \times \frac{1}{4}=16

E_{moon}=\frac{E_{earth}}{16}


Option 1)

\frac{E}{64}

Option 2)

\frac{E}{32}

Option 3)

\frac{E}{4}

Option 4)

\frac{E}{16}
Posted by

solutionqc

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 session 2 result date announced; Steps to check NTA session 2 scores
anam-khan

JEE Main 2024 session 2 final answer key soon at jeemain.nta.ac.in; result on April 25
anam-khan

JEE Main 2024 Session 2: Last day to challenge answer key today

Latest Question