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  • Answer please! A sphere of radius 1cm has potential of 8000V, then energy density near its surface will be

A sphere of radius 1cm has potential of 8000V, then energy density near its surface will be

  • Option 1)

    64\times105 J/m3

  • Option 2)

    8\times103 J/m3

  • Option 3)

    32 J/m3

  • Option 4)

    2.83 J/m3

 

Answers (1)

As we have learnt,

 

Energy density -

U_{v}=\frac{1}{2}\epsilon _{0}E^{2}

-

 

 Energy density 

u_e = \frac{1}{2}\times 8.86\times 10^{-12}\times \left (\frac{V}{R} \right )^2 = 2.83 J/m^3


Option 1)

64\times105 J/m3

Option 2)

8\times103 J/m3

Option 3)

32 J/m3

Option 4)

2.83 J/m3

Posted by

Vakul

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