If p, q, r, are real, p\neq q, then the roots of the equation (p-q)x^{2}-5(p+q)x-2(p-q)=0  are

  • Option 1)

    Real and equal

  • Option 2)

    Non real

  • Option 3)

    Real and unequal

  • Option 4)

    None of these

 

Answers (1)

As we learnt in 

Condition for Real and distinct roots of Quadratic Equation -

D= b^{2}-4ac> 0

- wherein

ax^{2}+bx+c= 0

is the quadratic equation

 

 \\( p-q) \right )x^{2}-5\left ( p+q \right )x-2\left ( p-q \right )=0\ \\\\\*\left\[ 5\left ( p+q \right ) \right ]^{2}-4\times \left ( -2 \right )\left ( p-q \right )^{2}\\*\\=25\left ( p+q \right )^{2}+8\left ( p-q \right )^{2}> 0


Option 1)

Real and equal

Incorrect

Option 2)

Non real

Incorrect

Option 3)

Real and unequal

Correct

Option 4)

None of these

Incorrect

Preparation Products

Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout BITSAT-JEE Main 2021

An exhaustive E-learning program for the complete preparation of JEE Main and Bitsat.

₹ 27999/- ₹ 16999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions