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  • Answer please! - Limit , continuity and differentiability - JEE Main-5

\lim_{x\rightarrow 1} \cos (lnx) equals 

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As we have learned

Limits of composite functions -

\lim_{x\rightarrow a}fog(x)=\lim_{x\rightarrow a}fg{(x)}
 

=\lim_{x\rightarrow b}f(x)
 

Where\:b=\lim_{x\rightarrow a}g(x)

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When x\rightarrow 1 then lnx\rightarrow 0 

\therefore \lim_{x\rightarrow 1} \cos (lnx )=\lim_{h\rightarrow 0}= 1

(where h= lnx)  

 

 

 

 


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Himanshu

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