Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

A cubical block of side 0.5 m floats on water with 30 % of its volume under water . What is the maximum weight that can be put on the block without fully submerging it under water ? [Take ,density of water = $10^{3}Kg/m^{3}$ ]
Option 1)
$46.3Kg$
Option 2)
$87.5Kg$
Option 3)
$65.4Kg$
Option 4)
$30.1Kg$

Answers (1)

best_answer

initial cond:

$B= mg$

$\left ( \rho \right )\left ( \frac{3}{10}Vg \right )=mg$

$\left ( 1000Kg/m^{3} \right )\left ( \frac{3}{10} \times (0.5)^3\right )=m$

$m=37.5Kg$

$finally \, \, \rho vg =\left ( m+M \right )g$

$\frac{\left ( m+M \right )g}{mg}=\frac{\rho Vg }{\rho \times \frac{3}{10}Vg}$

$1+\frac{M}{m}=\frac{10}{3}\Rightarrow \frac{M}{m}=\frac{7}{3}$

$M=\frac{7}{3}\left ( 37.5 \right )=87.3 Kg$

$=87.3 Kg$

Option 1)

$46.3Kg$

Option 2)
$87.5Kg$
Option 3)

$65.4Kg$

Option 4)

$30.1Kg$

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: At IIT Bombay, CSE remains top choice; closing rank falls by 2 points

anam-khan

JEE Main 2026 Registration LIVE: NTA session 1 application soon at jeemain.nta.nic.in; BTech exam dates

anam-khan

JEE Main 2026 Registration LIVE: NTA session 1 applications open soon at jeemain.nta.nic.in; exam dates out

Latest Question