Arrange the following compounds in increasing order of C-OH bond length:
methanol, phenol, p-ethoxyphenol
phenol < methanol < p-ethoxyphenol
methanol < p-ethoxyphenol < phenol
phenol <p-ethoxyphenol < methanol
methanol < phenol < p-ethoxyphenol
Phenol has one -OH group and the oxygen will resonate with benzene. Here the bond between O and C will double bond most of the time.
p-ethoxyphenol has one -OH group and one -OCH3 , from both groups oxygen will resonate with benzene. There are two oxygen is present, so they will resonate one by one. So, the Bond length between C and O will be larger here than phenol.
Methanol has one -OH group and there will be no resonating between C and O. So, the Length between C and O will be maximum.
The correct order of bond length is given below:
Phenol < p-ethoxyphenol < methanol
Therefore, Option(3) is correct.
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